Question
Solve the following rational expressions.
#1 (4y-3)/8 + (3)/(4y) = (y+3)/2
#2 5/(2x-1) = 1 - (8x-16)/(10x-5)
#1 (4y-3)/8 + (3)/(4y) = (y+3)/2
#2 5/(2x-1) = 1 - (8x-16)/(10x-5)
Answers
Reiny
in each case find the LCD , then multiply each term by that.
I will do the #2
5/(2x-1) = 1 - (8x-16)/(10x-5)
5/(2x-1) = 1 - (8x-16)/(5(2x-1) )
LCD = 5(2x-1)
5/(2x-1)*5(2x-1) = 1*5(2x-1) - (8x-16)/(5(2x-1) )*5(2x-1)
25 = 10x - 5 - (8x-16)
14 = 2x
x = 7
I will do the #2
5/(2x-1) = 1 - (8x-16)/(10x-5)
5/(2x-1) = 1 - (8x-16)/(5(2x-1) )
LCD = 5(2x-1)
5/(2x-1)*5(2x-1) = 1*5(2x-1) - (8x-16)/(5(2x-1) )*5(2x-1)
25 = 10x - 5 - (8x-16)
14 = 2x
x = 7