Asked by sayletyler
Solve the following rational equation for X: x^2 over x+5= 25 over x+5
Answers
Answered by
sayletyler
Few things, I need it simplified down to like 4 sentnces also can you say fractions like I did in my original question like x^2 Over the over is what im concerned about also {} these things and also any double parentesis I dont want them to know an Ai answered this
Answered by
sayletyler
Oh and no backwards slashes and I think i still see some of these {}
Answered by
sayletyler
That works thank you
Answered by
GPT-4o mini
To solve the rational equation
\[
\frac{x^2}{x+5} = \frac{25}{x+5},
\]
we can first eliminate the denominator (assuming \(x + 5 \neq 0\)) by multiplying both sides by \(x + 5\):
\[
x^2 = 25.
\]
Next, we solve the equation \(x^2 = 25\) by taking the square root of both sides:
\[
x = \pm 5.
\]
Now we have two potential solutions: \(x = 5\) and \(x = -5\).
However, we need to check if any of these solutions would make the original denominator zero, which would be problematic. The denominator \(x + 5 = 0\) when \(x = -5\). Thus, \(x = -5\) is not a valid solution.
The only valid solution is
\[
x = 5.
\]
Therefore, the solution to the equation is
\[
\boxed{5}.
\]
\[
\frac{x^2}{x+5} = \frac{25}{x+5},
\]
we can first eliminate the denominator (assuming \(x + 5 \neq 0\)) by multiplying both sides by \(x + 5\):
\[
x^2 = 25.
\]
Next, we solve the equation \(x^2 = 25\) by taking the square root of both sides:
\[
x = \pm 5.
\]
Now we have two potential solutions: \(x = 5\) and \(x = -5\).
However, we need to check if any of these solutions would make the original denominator zero, which would be problematic. The denominator \(x + 5 = 0\) when \(x = -5\). Thus, \(x = -5\) is not a valid solution.
The only valid solution is
\[
x = 5.
\]
Therefore, the solution to the equation is
\[
\boxed{5}.
\]
Answered by
GPT-4o mini
To solve the rational equation \(\frac{x^2}{x+5} = \frac{25}{x+5}\), we first multiply both sides by \(x+5\) (assuming \(x \neq -5\)), resulting in \(x^2 = 25\). We then solve for \(x\), giving \(x = 5\) and \(x = -5\). However, \(x = -5\) makes the denominator zero, so it’s not a valid solution. Thus, the solution to the equation is \(\{5\}\).
Answered by
GPT-4o mini
To solve the rational equation x^2 over x + 5 = 25 over x + 5, we first multiply both sides by x + 5 (assuming x is not equal to -5), resulting in x^2 = 25. We then solve for x, giving us x = 5 and x = -5. However, x = -5 makes the denominator zero, so it’s not a valid solution. Therefore, the solution to the equation is 5.
Answered by
GPT-4o mini
You're welcome! If you have any more questions or need further assistance, feel free to ask. Good luck!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.