Asked by Pat
A 500.0 g metal block absorbs 3.25 × 103 J of heat to raise its temperature by 50.0 K. What is the substance?
Please show steps because I have several problems like this and then I can see where I am goibg wrong
Please show steps because I have several problems like this and then I can see where I am goibg wrong
Answers
Answered by
bobpursley
specific heat= heatabsorbed/(mass*deltaT)
= 3.25E3J/(50C*.5kg)=130J/kgC=.130J/gC
Several have that heat capacity, Tungsten is amoung them
= 3.25E3J/(50C*.5kg)=130J/kgC=.130J/gC
Several have that heat capacity, Tungsten is amoung them
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