Asked by fatih
an RlC circuit has a resistance of 4 kOhm, a capacitance of 33 uF, and an inductance of 23 H. if the frequency of the alternating current is 2/pi kHz, what is the phase shift between the current and the voltage.
Answers
Answered by
Henry
F = 2 / 3.14 = 0.6369 kHz. = 637 Hz.
R = 4,000 Ohms.
L = 23 h.
C = 33 uF.
Xl = 6.28*636.9*23 = 91994 Ohms.
Xc = 1 / (6.28*637*33*10^-6) = 7.58
Ohms.
tanA = (Xl-Xc) / R = 91986 / 4000 = 23.
A = 87.5 Deg., Inductive.
Therefore, the current lags the voltage
by 87.5 Deg.
R = 4,000 Ohms.
L = 23 h.
C = 33 uF.
Xl = 6.28*636.9*23 = 91994 Ohms.
Xc = 1 / (6.28*637*33*10^-6) = 7.58
Ohms.
tanA = (Xl-Xc) / R = 91986 / 4000 = 23.
A = 87.5 Deg., Inductive.
Therefore, the current lags the voltage
by 87.5 Deg.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.