Question
Consider a circuit with an RL series with L=0.09 H and R=0.05 Ohm. At t=0 the circuit is connected to a battery which provides V0=12 V.
(a)How long does it take to the current to equal a fraction 0.95 of the steady state current?
(b) What is the energy stored (in Joules) in the magnetic field when the current equals a fraction 0.95 of the steady state current?
(c) What is the total energy delivered (in Joules) by the battery up to the time t found in part (a) ?
(d) How much energy (in Joules) has been dissipated in the resistor?
(a)How long does it take to the current to equal a fraction 0.95 of the steady state current?
(b) What is the energy stored (in Joules) in the magnetic field when the current equals a fraction 0.95 of the steady state current?
(c) What is the total energy delivered (in Joules) by the battery up to the time t found in part (a) ?
(d) How much energy (in Joules) has been dissipated in the resistor?
Answers
Henry
I = E/R = 12/0.05 = 24q Amps = Steady-state current.
0.95I = 0.95 * 240 = 228A.
Vr + Vc = 12 Volts
228*00.05 + Vc = 12
Vc = 12-11.4 = 0.6 Volts = Voltage across coil when i = 0.95I steady-state
a. Vc = 12/e^(t/T) = 0.6
e^(t/T) = 12/0.6 = 20
t/T = Ln20 = 3.0
T = L/R = 0.09/0.05 = 1.8 s.
t/1.8 = 3
t = 5.4 s.
c. Energy = E*I*t = 12*228*5.4=14,774.4
Joules.
d. Energy = I^2*R*t = (228)^2*0.05*5.4 =
14,036 Joules.
0.95I = 0.95 * 240 = 228A.
Vr + Vc = 12 Volts
228*00.05 + Vc = 12
Vc = 12-11.4 = 0.6 Volts = Voltage across coil when i = 0.95I steady-state
a. Vc = 12/e^(t/T) = 0.6
e^(t/T) = 12/0.6 = 20
t/T = Ln20 = 3.0
T = L/R = 0.09/0.05 = 1.8 s.
t/1.8 = 3
t = 5.4 s.
c. Energy = E*I*t = 12*228*5.4=14,774.4
Joules.
d. Energy = I^2*R*t = (228)^2*0.05*5.4 =
14,036 Joules.
abdul rahman
Plz answer b part......(C) n (d) part are wrong !
Anonymous
wrong answer
Anonymous
please abdul answer of this question.
FLu
All of the answers are wrong! Please help!
FLu
sorry answer a) seems right the rest appears wrong though. Anyone for b),c),d)?
abdul rahman
plz do u hav answers for other edx HW Q's ????
FLu
Did you figure the above problem out Abdul?
Thank
Thank
FLu
I got d) 8165
you multiply 12/0.09
and than apply what Henry provided for answer c) 12*126*5.4=8165
It seems the numbers are getting mixed up, can someone figure out b) and c) with it?
thanks
you multiply 12/0.09
and than apply what Henry provided for answer c) 12*126*5.4=8165
It seems the numbers are getting mixed up, can someone figure out b) and c) with it?
thanks
FLu
I meant divide 12/0.09 and then multiply the result by 0.95 which is approx. 126
b) and c) anyone?
b) and c) anyone?
FLu
ANyone for Problem 2: Displacement Current a) please?
b) 0
Open Switch on an RL Circuit
b) and c) please?
b) 0
Open Switch on an RL Circuit
b) and c) please?
abdul rahman
flu do u hav answers for Q2 part a
Q3 part b and part c, Q5 and Q7 all parts ???
Q3 part b and part c, Q5 and Q7 all parts ???
My
Anyone for this please?
Problem 2: Displacement Current a) please?
Problem: Open Switch on an RL Circuit
b) and c) please?
Problem 2: Displacement Current a) please?
Problem: Open Switch on an RL Circuit
b) and c) please?
Ira
Yes, please the question below too?!
Problem 2: Displacement Current a)
Problem: Open Switch on an RL Circuit
b) and c)
Problem 2: Displacement Current a)
Problem: Open Switch on an RL Circuit
b) and c)
FLu
Can somebody help with Problem: Displacement Current please?
I thought the formula is:
(1.25663706*10^-6*0.04*0.2*0.0705)/(2*pi*0.05^2)
However, I am not getting the correctr answer.
I thought the formula is:
(1.25663706*10^-6*0.04*0.2*0.0705)/(2*pi*0.05^2)
However, I am not getting the correctr answer.
dd
i need only the c1
ev
C2: integral 1 to 5.4 of (12/0.05)^2)* (1-e^(-(0.05 t)/0.09))^2 * 0.05 dt
C1: B + C2
C1: B + C2
Supraconductor
remember that E=1/2.L.I² for b)
Ur
Anybody figure out c)?
FLu
Anyone for Problem
Opening a Switch on an RL Circuit
c) please?
Opening a Switch on an RL Circuit
c) please?
Supraconductor
Flu > ev give you the answer d (just integrate what he wrote)
now you have d) you have just to do answer c) = b) + d)
now you have d) you have just to do answer c) = b) + d)