Question

In a circuit with resistance 10 ohms, power 𝑃 (measured in watts) is equal to 10𝐼2 , where 𝐼 is the current measured in amperes. When 𝐼=6 amperes, what is the rate of change of 𝑃 with respect to 𝐼 ?

Answer 1

P = <i>I</i>^2 R = 10<i>I</i>^2
dP/d<i>I</i> = 2<i>I</i>
so plug in your numbers