1
32
58
1. logx+log(x+48)=2
14.log50+log(x/2)=2
23.log72-log(2x/3)=0
Could someone please explain to me how to solve these?
4 answers
thanks, but how do i solve them?
remember the rule of logs?
Log (ab)= loga + logb so, take 14 as an example:
log50 + log(x/2)=2
log(50x/2)=2
50x/2= antilog2
solve for x
On 23, the formula is
log(a/b)= loga - logb
Log (ab)= loga + logb so, take 14 as an example:
log50 + log(x/2)=2
log(50x/2)=2
50x/2= antilog2
solve for x
On 23, the formula is
log(a/b)= loga - logb
thanks!
1 answer