8.94g CuCl2 x (atomic mass Cu/molar mass CuCl2) = ? g Cu = theoretical yield.
%yield = (actual yield/theoretical yield)*100 = ?
If 2.68 grams of Copper was recovered and you started with 8.94 grams of Copper(II)chloride,then what is the percent yield of the reaction?
3 answers
I don't understand it.Please help me!
You don't understand what part?
You start with 8.94 g CuCl2. You can obtain, if everything goes right and you have 100% on results, about 4.22 g. You recovered only 2.68g.
% yield or % recovery = (2.68/4.22)*100 = ?
You start with 8.94 g CuCl2. You can obtain, if everything goes right and you have 100% on results, about 4.22 g. You recovered only 2.68g.
% yield or % recovery = (2.68/4.22)*100 = ?
1 answer