Asked by linda
If 2.68 grams of Copper was recovered and you started with 8.94 grams of Copper(II)chloride,then what is the percent yield of the reaction?
Answers
Answered by
DrBob222
8.94g CuCl2 x (atomic mass Cu/molar mass CuCl2) = ? g Cu = theoretical yield.
%yield = (actual yield/theoretical yield)*100 = ?
%yield = (actual yield/theoretical yield)*100 = ?
Answered by
linda
I don't understand it.Please help me!
Answered by
DrBob222
You don't understand what part?
You start with 8.94 g CuCl2. You can obtain, if everything goes right and you have 100% on results, about 4.22 g. You recovered only 2.68g.
% yield or % recovery = (2.68/4.22)*100 = ?
You start with 8.94 g CuCl2. You can obtain, if everything goes right and you have 100% on results, about 4.22 g. You recovered only 2.68g.
% yield or % recovery = (2.68/4.22)*100 = ?
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