How many grams of copper are contained in 253g of CuSO4

Answer 1

Some information is missing for the question. There needs to be an equation to go along with this.

I will give you the general way to do a problem like this, but this is not the answer to your specific problem, you will have to use your given equation to get the correct answer.

For this question, you would have to do a couple conversions. One thing any chemistry professor will tell you is to always GO TO MOLES first.

So you have 253 g CuSO4. Convert this to moles by the use of the molecular weight. MW of CuSO4 = 159.62 g
253 g CuSO4 x (1 mole CuSO4/159.62 g) = 1.585 moles CuSO4

This is where you are missing some information. There needs to be an equation to say how many moles are used of each. For example, say the equation was: 1 CuSO4 <--> 1 Cu + 1 SO4.

You would use a 1:1 mole ratio because for every one CuSO4, there is one Cu.

Pertaining to the example equation I gave, you would then take the moles of CuSO4 and convert to moles of Cu.
1.585 moles CuSO4 x (1 mole Cu/1 mole CuSO4) = 1.585 moles Cu

Then you would need to convert back to grams of Cu. MW of Cu = 63.55 g
1.585 moles Cu x (63.55 g/1 mole Cu) = 100.73 g Cu.

Answer 2

Lindsay - copper does not have a MW it has an atomic mass. The answer 100.73 g has too many sig figs.

There is no necessary information missing in the question and there is no need to use moles. It is a question based on simple ratios.

Atomic mass for copper is 63.55 g
the molecular mass of CuSO4 is 159.6 g

Thus 159.62 g contains 63.55 g of copper

so 253 g contains 63.55 x 253 g/158.6

= 101 g (to 3 sig figs as the minimum number of sig figs in the calculation is 3)

Answer 3

OOps a typo has crept in!

so 253 g contains 63.55 x 253 g/159.6

= 101 g (to 3 sig figs as the minimum number of sig figs in the calculation is 3)