Asked by Durbin23
How many grams of copper are deposited on the cathode of an electrolytic cell if an electric current of 2.00 A is passed through a solution of CuSO4 for a period of 19.0 min?
Answers
Answered by
DrBob222
coulombs - A x seconds = ?
096,485 coulombs will deposit 63.55/2 g Cu = approx 32 but you need a better number than that.
Then 32? x coulombs/96,485 = g Cu deposited.
096,485 coulombs will deposit 63.55/2 g Cu = approx 32 but you need a better number than that.
Then 32? x coulombs/96,485 = g Cu deposited.
Answered by
Durbin23
what are the coulombs? how do I find them?
and also where can I find that equation?
and also where can I find that equation?
Answered by
DrBob222
See my first line. Not only did I tell you that you needed coulombs but I told you how to calculate it.
coulombs = A x seconds.
amperes in the problem = 2.00 A.
time in the problem = 19.0 min or 19.0 x (60 seconds/min) = ? seconds so
coulombs = 2.00 x 19.0 x 60 = >
coulombs = A x seconds.
amperes in the problem = 2.00 A.
time in the problem = 19.0 min or 19.0 x (60 seconds/min) = ? seconds so
coulombs = 2.00 x 19.0 x 60 = >
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.