Asked by sierra
A cube of lead measuring 1 meter on each side is thrown into the ocean. Determine the buoyant force acting on this mass of lead. The density of lead is 11.4 grams/ cubic centimeter
Answers
Answered by
Elena
Law of Archimedes:The buoyant force is equal to the weight of the replaced water or gas.
Weight of replaced water is
mg=ρ•V•g= ρ•a^3•g=1025•1•9.8=10045 N
(ρ is the density of sea water)
Weight of replaced water is
mg=ρ•V•g= ρ•a^3•g=1025•1•9.8=10045 N
(ρ is the density of sea water)
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