Question

The lenth of a room is 3 more thean twice the width of the room. The perimeter of the room is 66 feet. What are the dimensions of the room?
(Let x=the width fo the room.)

Book gives the following for the answer:

x + x =(3 + 2x) + (3 + 2x)=66

width=10, lenth=23

I am not clear how to set up the equation for this word problem and how to calculate it out?

Answer 1

The first = sign should be +.
You can make x the width of the room.
The length will then be 2x+3, since it is 3 more than twice the width.
Now, just add up the four sides, which =66. Your equation will be
x + x +(2x + 3) + (2x + 3) = 66
Combine like terms and you have
6x + 6 = 66
To solve this equation, subtract 6 from both sides. You now have
6x = 60
Now, divide both sides by 6 to get x by itself
x = 10 (width) and (2x+3)=23 (length)

Answer 2

Possible Correct Answer: 10, 23
Answer: Width = 10 feet, Length = 23 feet

The perimeter of a room is twice the length plus twice the width. Since x is the width, the length of the room is (3 + 2x). Using this, the equation is:

x + x + (3 + 2x) + (3 + 2x) = 66

Solve this equation. First, simplify the left side by combining like terms:

6x + 6 = 66.
Subtract 6 from both sides:
6x = 60
Divide both sides by 6:
x = 10.

So, the width is 10 feet and the length is 23 feet.

Answer 3

Yes, that is correct!