The floor plan of a room has a scale of 2.5in : 35ft. In the drawing, the length of the room is 8in. and the width of the room is 6in. What is the perimeter of the actual room? *

8/x = 2.5/35

x = 112
6/8 * 112 = 84
so the room is 84 x 112 ft, with perimeter
p = 2(84+112) ft

not was i looking for but thx

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To calculate the perimeter of the actual room, we need to convert the measurements from inches to feet using the given scale of 2.5in : 35ft.

First, let's calculate the length of the room in feet:
Length of the room in feet = (Length on the drawing / Scale) = (8in / 2.5in) * 35ft = (8/2.5) * 35ft = 11.2ft

Next, let's calculate the width of the room in feet:
Width of the room in feet = (Width on the drawing / Scale) = (6in / 2.5in) * 35ft = (6/2.5) * 35ft = 84ft

Now, we can calculate the perimeter of the actual room:
Perimeter of the room = 2 * (Length of the room + Width of the room) = 2 * (11.2ft + 84ft) = 2 * 95.2ft = 190.4ft

Therefore, the perimeter of the actual room is 190.4 feet.