Asked by Monica
Two charged particles of equal magnitude (+Q and −Q) are fixed at opposite corners of a square that lies in a plane (see figure below). A test charge +q is placed at a third corner.
+Q
+q −Q What is the direction of the force on the
test charge due to the two other charges?
+Q
+q −Q What is the direction of the force on the
test charge due to the two other charges?
Answers
Answered by
drwls
45 degrees below the line connecting +q to -Q
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