Asked by samuel

Two charged particles are 8.5cm apart .They moved and the force on each of them is found to be tripled .How far apart are they now

Answers

Answered by Damon
F = constant / d^2
3 F = constant /x^2

F = c/(8.5^2)
3 F = 3c/(8.5^2) = c/x^2
3 x^2 = 8.5^2
x = 8.5/sqrt(3)
Answered by Scott
electric field strength follows the inverse square law

f d^2 = (3f) D^2

D^2 = d^2 / 3

D = 8.5 / √3
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