Asked by iowa
There are two charged particles. They exert an electrostatic force of 10 N on each other. Suppose the distance between the two particles is increased to five times the original distance. What will the magnitude of the force?
Answers
Answered by
Steve
since F = qq/r^2, changing r to 5r means you now have
qq/(5r)^2 = qq/25r^2 = 1/25 * qq/r^2 = 1/25 F
qq/(5r)^2 = qq/25r^2 = 1/25 * qq/r^2 = 1/25 F
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