Question
The equilibrium constant, Kc for the system,
CaO(s) + CO2(g) == CaCO3(s), is
A. Kc = (CaO) (CO2) / (CaCO3)
B. Kc = (CO2)
C. Kc = (CaCO3)/(CaO)
D. Kc = (CaCO3) / (CaO) (CO2)
E. Kc = 1 / (CO2)
My answer is (CaCo3) / (CaO)(CO2). Would you agree?
CaO(s) + CO2(g) == CaCO3(s), is
A. Kc = (CaO) (CO2) / (CaCO3)
B. Kc = (CO2)
C. Kc = (CaCO3)/(CaO)
D. Kc = (CaCO3) / (CaO) (CO2)
E. Kc = 1 / (CO2)
My answer is (CaCo3) / (CaO)(CO2). Would you agree?
Answers
No. Solids aren't included in K. Neither are pure liquids.
K = 1/(CO2)
K = 1/(CO2)
Oh wow I didn't even realize that they were both solids, I understand thank you!!
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