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Asked by Courtney

How do I find the indefinite integral of cosx/(1-cos^2 x)dx?
13 years ago

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Answered by Reiny
cosx/(1-cos^2 x)
= cosx/(sin^2 x)
= (cosx/sinx)(1/sinx)
= cotx cscx

I just happen to know, as should you, that the derivative of cscx = -cotx cscx

so ∫cosx/(1-cos^2 x) dx = - cscx
13 years ago
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How do I find the indefinite integral of cosx/(1-cos^2 x)dx?

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