Asked by calculus100
Find the following indefinite integrals.
∫(cos(t)) / (9sin(t)+10)^(2) dt
∫(cos(t)) / (9sin(t)+10)^(2) dt
Answers
Answered by
oobleck
let u = 9sint+10
then du = 9cost, and so cost = 1/9 du
So, your integral becomes
∫ 1/9 du/u^2
then du = 9cost, and so cost = 1/9 du
So, your integral becomes
∫ 1/9 du/u^2
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