Asked by victoria
integral from 1 to 0 of e^2x dx=
a)e^2x-1
b)e^2
c)(e^2/2)
d)(e^2-1)/2
e)2e^2-2
a)e^2x-1
b)e^2
c)(e^2/2)
d)(e^2-1)/2
e)2e^2-2
Answers
Answered by
Steve
1/2 e^2x[1,0]
1/2(e^2 - e^0)
(d)
1/2(e^2 - e^0)
(d)
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