Asked by janny

Suppose a simple pendulum is used to measure the acceleration due to gravity at various points on the Earth. If g varies by 0.151 % over the various locations where it is sampled, what is the corresponding variation in the period of the pendulum? Assume that the length of the pendulum does not change from one site to another
Answered by bobpursley
deltaT=sqrt(deltag/g)=sqrt(.00151)
Answered by Steve
dpnt know
Answered by KIRAN MUGHAL
WHEN THE PENDULUM IS ON THE RIGHT ITS RIGHT SO RIGHT IS RIGHT BUT RIGHT IS WRONG
DUE TO YOUR QUESTION U ARE STUPID THANKS HAHAHAHAHA
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