Asked by Emily

How many milliliters of .100 M HNO3 are needed to neutralize 58.5 mL of .0100 Al(0H)3?

Answers

Answered by DrBob222
3HNO3 + Al(OH)3 ==> Al(NO3)3 + 3H2O
How many mols Al(OH)3 do you have? That is M x L = ?

So how many mols HNO3 are needed to neutralize it. The equations tells you moles HNO3 = 3* moles Al(OH)3.

Then M HNO3 = moles HNO3/L HNO3.
You have M and moles solve for L HNO3 an convert to mL.
Answered by Jess
17.6 mL
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