Asked by joe walker
How many milliliters of a 3.00 M solution of hydrochloric acid are needed to completely react with 25.0 g of zinc sulfide according to the chemical reaction shown below?
ZnS(s) + 2HCl(aq) ? ZnCl2(aq) + H2S(l)
(Answer to three significant digits.)
_____ mL of 3.00 M hydrochloric acid
ZnS(s) + 2HCl(aq) ? ZnCl2(aq) + H2S(l)
(Answer to three significant digits.)
_____ mL of 3.00 M hydrochloric acid
Answers
Answered by
DrBob222
You have the balanced equation.
Follow the instructions at this link to convert 25.0g ZnS to moles HCl.
Then M HCl = moles HCl/L HCl, solve for L HCl and convert to mL.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Follow the instructions at this link to convert 25.0g ZnS to moles HCl.
Then M HCl = moles HCl/L HCl, solve for L HCl and convert to mL.
http://www.jiskha.com/science/chemistry/stoichiometry.html
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