Question
To find the distance from the house at point D to the house at point E, a surveyor measures ÚDFE, which he finds is 73‹40'. The distance from the house at point D to point F is 15 ft, and the distance from point F to the house at point E is 28 ft. How far apart are the houses?
Answers
this one is just like the one with bearings. Use law of cosines:
DE<sup>2</sup> = FD<sup>2</sup> + FE<sup>2</sup> - 2*FD*FE*cosF
DE<sup>2</sup> = 225 + 784 - 2*15*28*cos(73.666666)
DE<sup>2</sup> = 773
DE = 28
DE<sup>2</sup> = FD<sup>2</sup> + FE<sup>2</sup> - 2*FD*FE*cosF
DE<sup>2</sup> = 225 + 784 - 2*15*28*cos(73.666666)
DE<sup>2</sup> = 773
DE = 28
Thank you so much!