Find the distance between the points (-5, 2) and (-6, 10).
You can use the distance formula, but it is not on the formula sheet and is hard to use.
It is easier to plot it on the coordinate plane - Use the Desmos graphing calculator to plot the points, drop the right triangle, and use the Pythagorean Theorem.
(1 point)
Responses
The vertical distance is 8 and the horizontal distance is 1; answer approximately 8.1 units
The vertical distance is 11 and the horizontal distance is 12; answer approximately 16.3 units
The vertical distance is 1 and the horizontal distance is 8; answer approximately 8.1 units
The vertical distance is 12 and the horizontal distance is 11; answer approximately 16.3 units
3 answers
The vertical distance is 8 and the horizontal distance is 1; answer approximately 8.1 units
explain how that is the correct answer
To find the distance between the points (-5, 2) and (-6, 10), you can create a right triangle using these two points and a vertical or horizontal line.
The vertical distance between the two points is 10 - 2 = 8 units.
The horizontal distance between the two points is -6 - (-5) = -1 unit (you can also think of it as 5 - 6 = 1 unit).
Now, you have a right triangle with the vertical side being 8 units and the horizontal side being 1 unit. Using the Pythagorean Theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides, you can find the distance between the two points:
c² = a² + b²
c² = 1² + 8²
c² = 1 + 64
c² = 65
c ≈ √65 ≈ 8.1 units
Therefore, the distance between the points (-5, 2) and (-6, 10) is approximately 8.1 units.
The vertical distance between the two points is 10 - 2 = 8 units.
The horizontal distance between the two points is -6 - (-5) = -1 unit (you can also think of it as 5 - 6 = 1 unit).
Now, you have a right triangle with the vertical side being 8 units and the horizontal side being 1 unit. Using the Pythagorean Theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides, you can find the distance between the two points:
c² = a² + b²
c² = 1² + 8²
c² = 1 + 64
c² = 65
c ≈ √65 ≈ 8.1 units
Therefore, the distance between the points (-5, 2) and (-6, 10) is approximately 8.1 units.