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Find the distance between ─19 and 4 on a number line.



__ unit(s)

19 answers

To find the distance between -19 and 4 on a number line, you can use the formula for distance between two points \( a \) and \( b \):

\[ \text{Distance} = |a - b| \]

In this case, \( a = -19 \) and \( b = 4 \).

Now calculate:

\[ \text{Distance} = |-19 - 4| = |-19 - 4| = |-23| = 23 \]

Therefore, the distance between -19 and 4 is 23 units.

The highest and lowest recorded temperatures for the state of Michigan are 112° Fahrenheit and ─51° Fahrenheit. Find the range in these extreme temperatures.

To find the range of recorded temperatures, you subtract the lowest temperature from the highest temperature. The highest recorded temperature is 112° Fahrenheit, and the lowest recorded temperature is -51° Fahrenheit.

The formula for finding the range is:

\[ \text{Range} = \text{Highest temperature} - \text{Lowest temperature} \]

Substituting the values:

\[ \text{Range} = 112 - (-51) = 112 + 51 = 163 \]

Thus, the range of the extreme temperatures in Michigan is 163° Fahrenheit.

Avery is playing a board game with her friends. The table shows the results after her first two turns.



Turn Change in Position
1 Move back 4 spaces
2 Move forward 11 spaces


How much greater is the result of Avery's second turn than the result of her first turn?

To find out how much greater the result of Avery's second turn is than her first turn, we first need to determine her position changes after each turn.

  1. First Turn: Avery moves back 4 spaces. This change in position can be represented as: \[ \text{Position after Turn 1} = -4 \]

  2. Second Turn: Avery moves forward 11 spaces. This change in position can be represented as: \[ \text{Position after Turn 2} = +11 \]

Now, to find out how much greater the result of the second turn is than that of the first turn, we find the difference between the two results:

\[ \text{Difference} = \text{Position after Turn 2} - \text{Position after Turn 1} \] \[ \text{Difference} = 11 - (-4) = 11 + 4 = 15 \]

Thus, the result of Avery's second turn is 15 spaces greater than the result of her first turn.

Subtract: 15−28=

To subtract \( 15 - 28 \), you can follow these steps:

  1. Since 28 is larger than 15, the result will be negative.
  2. You can rewrite the expression as \( - (28 - 15) \).

Now, calculate \( 28 - 15 \):

\[ 28 - 15 = 13 \]

Thus,

\[ 15 - 28 = -13 \]

Therefore, \( 15 - 28 = -13 \).

The distance between 15
and 28
on a number line is 2 of 2.
Select Choice
unit(s).

To find the distance between 15 and 28 on a number line, you can use the formula for distance:

\[ \text{Distance} = |a - b| \]

where \( a \) and \( b \) are the two points. In this case, let \( a = 28 \) and \( b = 15 \):

\[ \text{Distance} = |28 - 15| = |13| = 13 \]

Therefore, the distance between 15 and 28 is 13 unit(s).

−60−(−27)

To simplify the expression \(-60 - (-27)\), you can follow these steps:

  1. Change the subtraction of a negative number to addition: \[ -60 - (-27) = -60 + 27 \]

  2. Now perform the addition: \[ -60 + 27 = -33 \]

Therefore, \(-60 - (-27) = -33\).

The distance between −60
and −27
on a number line is 2 of 2.
Select Choice
unit(s).

To find the distance between \(-60\) and \(-27\) on a number line, you can use the distance formula:

\[ \text{Distance} = |a - b| \]

where \( a = -27 \) and \( b = -60 \). Thus, you have:

\[ \text{Distance} = |-27 - (-60)| = |-27 + 60| = |33| \]

Therefore, the distance between \(-60\) and \(-27\) is 33 unit(s).

Find 45−310
. Write your answer as a fraction or mixed number in simplest form.

To find the expression \( 45 - \frac{3}{10} \), first, we need to express 45 as a fraction with a denominator of 10.

  1. Convert 45 to a fraction: \[ 45 = \frac{45 \times 10}{10} = \frac{450}{10} \]

  2. Now, subtract \(\frac{3}{10}\) from \(\frac{450}{10}\): \[ 45 - \frac{3}{10} = \frac{450}{10} - \frac{3}{10} = \frac{450 - 3}{10} = \frac{447}{10} \]

  3. To express \(\frac{447}{10}\) as a mixed number:

    • Divide 447 by 10. The quotient is 44, and the remainder is 7.
    • Thus, \[ \frac{447}{10} = 44 \frac{7}{10} \]

Therefore, the answer is \( \frac{447}{10} \) or as a mixed number: \( 44 \frac{7}{10} \).

4/5−/310

To subtract \(\frac{3}{10}\) from \(\frac{4}{5}\), we need to have a common denominator.

  1. Find a common denominator for \(\frac{4}{5}\) and \(\frac{3}{10}\). The least common multiple of 5 and 10 is 10.

  2. Convert \(\frac{4}{5}\) to a fraction with a denominator of 10: \[ \frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10} \]

  3. Now, subtract \(\frac{3}{10}\) from \(\frac{8}{10}\): \[ \frac{8}{10} - \frac{3}{10} = \frac{8 - 3}{10} = \frac{5}{10} \]

  4. Simplify \(\frac{5}{10}\): \[ \frac{5}{10} = \frac{1}{2} \]

Therefore, \( \frac{4}{5} - \frac{3}{10} = \frac{1}{2} \).

4/5−3/10

To subtract \(\frac{3}{10}\) from \(\frac{4}{5}\), we need to find a common denominator. The least common multiple of 5 and 10 is 10.

  1. Convert \(\frac{4}{5}\) to a fraction with a denominator of 10: \[ \frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10} \]

  2. Now, subtract \(\frac{3}{10}\) from \(\frac{8}{10}\): \[ \frac{8}{10} - \frac{3}{10} = \frac{8 - 3}{10} = \frac{5}{10} \]

  3. Simplify \(\frac{5}{10}\): \[ \frac{5}{10} = \frac{1}{2} \]

Therefore, the result of \( \frac{4}{5} - \frac{3}{10} \) is \(\frac{1}{2}\).