Asked by Melissa
A wire of length L and cross-sectional area A has resistance R. What will be the resistance R_stretched of the wire if it is stretched to twice its original length? Assume that the density and resistivity of the material do not change when the wire is stretched.
Express your answer in terms of the wire's original resistance R.
Express your answer in terms of the wire's original resistance R.
Answers
Answered by
drwls
The product L*A remains constant after stretching. If L doubles, A decreases by 1/2
Resistance is proportional to L/A.
R2/R1 = L2/L1 *A1/A2 = 4
R1 is the original resistance and R2 is the final resistance.
Resistance is proportional to L/A.
R2/R1 = L2/L1 *A1/A2 = 4
R1 is the original resistance and R2 is the final resistance.
Answered by
If the diamèter of the wire is doubled and its length is halved then its young's modulus
A)becomes double B)remains same C)becomes half C)becomes square
Answered by
If the diamèter of the wire is doubled and its length is halved then its young's modulus
Remain same
Answered by
MANIRAGUHA Eric
Consider a c-Si solar cell whose fingers have a resistance R=0.1 Ohm. What would be the finger's resistance (in Ohm) if the finger's width is doubled and the finger's height is one third of its initial value?
Answered by
Oliver
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