Asked by Katie
                Write the balanced chemical equation for each of these reactions. Include phases. When aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms. However, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble [Pb(OH)4]2–(aq) complex ion.
            
            
        Answers
                    Answered by
            DrBob222
            
    2NaOH(aq) + Pb(NO3)2(aq) ==> Pb(OH)2(s) + 2NaNO3(aq)
Pb(OH)2(s) + 2NaOH(aq) ==> Na2Pb(OH)4(aq)
 
    
Pb(OH)2(s) + 2NaOH(aq) ==> Na2Pb(OH)4(aq)
                    Answered by
            Sarah
            
    I had the exact same question, but the when I tried the second equation, it was wrong. 
    
                    Answered by
            Massie
            
    Same as Sarah
    
                    Answered by
            Anonymous
            
    second equation is
Pb(OH)2(s)+2OH^-(aq)<---> [Pb(OH)4]^2-(aq)
    
Pb(OH)2(s)+2OH^-(aq)<---> [Pb(OH)4]^2-(aq)
                    Answered by
            Anonymous
            
    You forgot the 2Na+(aq) ions as products of the second reaction.
    
                    Answered by
            Anya
            
    You have to put " Pb(OH)4(aq) " in square brackets... [Pb(OH)4]2–(aq) 
    
                    Answered by
            Yugi
            
    The answer for the second equation input is
Pb(OH)2 (s) + 2 NaOH^- (aq) --> [Pb(OH)4]^2- (aq) + 2 Na^+ (aq)
This part of the problem annoyed the hell out of me before I actually got it.
    
Pb(OH)2 (s) + 2 NaOH^- (aq) --> [Pb(OH)4]^2- (aq) + 2 Na^+ (aq)
This part of the problem annoyed the hell out of me before I actually got it.
                    Answered by
            Andrew
            
    Pb(OH)2 (s) + 2NaOH (aq) <--> [Pb(OH)4]^2- + 2Na^+ (aq)
Don't include the "-" in NaOH
    
Don't include the "-" in NaOH
                    Answered by
            Juan Imhoff
            
    Ole ole Pumas!
The answer in right
    
The answer in right
                    Answered by
            RONNIE
            
    Na2Pb(OH)H(aq)
    
                    Answered by
            Tamerra
            
    2NaOH(aq)+Pb(NO3)2(aq)--->Pb(OH)2(s)+2NaNO3(aq)
Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)
just saw the answer on sapling.
    
Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)
just saw the answer on sapling.
                    Answered by
            Violet
            
    I can confirm Tamerra's answer. 
2NaOH(aq)+Pb(NO3)2(aq)--->Pb(OH)2(s)+2NaNO3(aq)
Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)
is the correct answer on Sapling.
    
2NaOH(aq)+Pb(NO3)2(aq)--->Pb(OH)2(s)+2NaNO3(aq)
Pb(OH)2(s)+2OH^-(aq)--->[Pb(OH)4]^2-(aq)
is the correct answer on Sapling.
                    Answered by
            Anonymous
            
    Not correct on sapling
    
                    Answered by
            Dev
            
    Ok, here is the final answer that worked for mines on Sapling
1: 2NaOH(aq) + Pb(NO3)2(aq) --> Pb(OH)2(s) + 2NaNO3(aq)
2: Pb(OH)2(s) + 2OH^-(aq) --> [Pb(OH)4]^2-(aq)
    
1: 2NaOH(aq) + Pb(NO3)2(aq) --> Pb(OH)2(s) + 2NaNO3(aq)
2: Pb(OH)2(s) + 2OH^-(aq) --> [Pb(OH)4]^2-(aq)
                    Answered by
            Anonymous
            
    2NaOH(aq) + Pb(NO3)2(aq)-----> Pb(OH)2(s) + 2NaNO3(aq) 
**** for Pb(NO3)2 the 2 does not mean to square it you have to put it in the bottom corner as well as Pb(OH)2 the 2 does not mean to square it has to be put in the bottom corner
Pb(OH)2(s) +2OH-(aq)----->[Pb(OH)4]2-(aq)
****for Pb(OH)2 the 2 does not mean to square it you have to put it in the bottom corner
****in [Pb(OH)4]2- the 2- IS SQUARED and the 4 is in the bottom corner
    
**** for Pb(NO3)2 the 2 does not mean to square it you have to put it in the bottom corner as well as Pb(OH)2 the 2 does not mean to square it has to be put in the bottom corner
Pb(OH)2(s) +2OH-(aq)----->[Pb(OH)4]2-(aq)
****for Pb(OH)2 the 2 does not mean to square it you have to put it in the bottom corner
****in [Pb(OH)4]2- the 2- IS SQUARED and the 4 is in the bottom corner
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