Asked by Katelyn

Jane and John, with masses of 50 kg and 60 kg, respectively, stand on a frictionless surfact 10 m apart. John pulls on a rope that connects him to Jane, giving Jane an acceleration of 0.92 m/s^2 toward him. (a) What is John's acceleration? (b) If the pulling force is applied constantly, where will Jane and John meet?

Answers

Answered by Anonymous
.77
45.5
Answered by Sophia
A.)
F=ma
F= (50kg)(.92m/s^2)
F= 46N

a= 46N/60kg
a= 0.77m/s^2 toward Jane
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