Question

when 7.50 grams of iodine (I2) is added to 48.7grams of carbon tetrachloride (CCl4), the iodine dissolves and a solution is formed. The weight percent of the iodine in the solution is?

7.50g I2/ 7.50 + 48.7 X 100 = 13.3

Did I do this correctly?
Yes, but to avoid your calculation being misinterpreted I would show it this way.
(7.50/7.50+48.7) x 100 = 13.3%

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