Question

Dye of iodine is prepared by dissolving in ethanol , and 1% ( one percent ) of this solution contains 10 g of solute in 1000 g of solution
1) how many grams of solvent is there in the solution ?
2) how many moles of solute ( I2) is there?
3) what is the molality of 1% of this solution ?

and can we find the molarity of solution ?

Answer 1

1. 1% means 1g I2/100 g solution = 10g I2/1000g solution = 10g I2/(10g I2+ 990g ethanol)
2. mol I2 = grams/molar mass
3. m = mols/kg solvent = ?

You can convert to M if you know the density of the solution.