WEll, follow the formula...
amountremaining=Original*e^(-.692t/13)
3.29/26/3= e^(-.692t/13)
take the ln of each side
-.207 = -.692t/13
solve for t in days.
There are 3.29g of iodine -126 remaining in a smple originally containing 26.3 g of Iodine - 126 the half life of Iodine - 126 is 13 days. How old is the sample?
At study hall test is after lunch and cant figure out htese 2 on my review packet
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