Asked by Alex
A graduated cylinder was used to transfer 201 mL of a 0.478 M solution of KCl to a beaker which was subsequently diluted to a final volume of 1.092 L. What is the final molarity of the KCl in the beaker after the solution is thoroughly mixed?
Answers
Answered by
DrBob222
The calculation is done this way.
0.478M x (201 mL/1092 mL) = ?
I don't know if this is a play on significant figures; I ask because measuring 201 mL with a graduated cylinder is not very accurate. I expect the amount actually transferred was between 199 and 201 and perhaps not even that close.
0.478M x (201 mL/1092 mL) = ?
I don't know if this is a play on significant figures; I ask because measuring 201 mL with a graduated cylinder is not very accurate. I expect the amount actually transferred was between 199 and 201 and perhaps not even that close.
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