Asked by timmy
A graduated cylinder contains 17.0 mL of water. What is the new water level after 31.6 g of silver metal with a density of 10.5 g/mL is submerged in the water
Answers
Answered by
DrBob222
What is the volume of the silver metal? That's volume = mass/density = ?
Then that volume will displace the water in the graduated cylinder the same amount so 17.0 + volume Ag = new volume in mL.
Then that volume will displace the water in the graduated cylinder the same amount so 17.0 + volume Ag = new volume in mL.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.