Question
a graduated cylinder contains 135 ml of water. a 11.0 g piece of iron (d=7.86g/ml ) and a 24.0 g piece of lead (d=11.3g/ml) are added. what is the new water level in the cylinder?
Answers
Mass = volume x density
volume Pb = mass/density
volume Fe = mass/density
Total volume Fe&Pb=volume Pb + volume Fe
Total volume in cylinder = volume water + volume of Pb & Fe.
volume Pb = mass/density
volume Fe = mass/density
Total volume Fe&Pb=volume Pb + volume Fe
Total volume in cylinder = volume water + volume of Pb & Fe.
I'm lost in which number goes where
C'mon. It makes no sense to me that you don't know which number goes where.
volume Pb = mass/density.
mass Pb = 24.0 g. Right? It says that in the problem.
density = 11.3 g/mL. Right? It says that in the problem.
I think you want someone to work the problem for you.
volume Pb = mass/density.
mass Pb = 24.0 g. Right? It says that in the problem.
density = 11.3 g/mL. Right? It says that in the problem.
I think you want someone to work the problem for you.
Related Questions
you have 100.0-mL graduated cylinder containing 50.0 mL of water. you drop a 124-g piece of brass (d...
A graduated cylinder contains 155mL mL of water. A 17.0g g piece of iron (density = 7.86g/cm 3 g/cm...
Iron has density 7.87 g/cm3. If 52.3 g of iron is added to 74.5 mL of water in a graduated cylinder,...
100 ml graduated cylinder containing 50 ml of water, drop 100g piece of brass into the water what he...