Asked by Anonymous
a graduated cylinder contains 135 ml of water. a 11.0 g piece of iron (d=7.86g/ml ) and a 24.0 g piece of lead (d=11.3g/ml) are added. what is the new water level in the cylinder?
Answers
Answered by
DrBob222
Mass = volume x density
volume Pb = mass/density
volume Fe = mass/density
Total volume Fe&Pb=volume Pb + volume Fe
Total volume in cylinder = volume water + volume of Pb & Fe.
volume Pb = mass/density
volume Fe = mass/density
Total volume Fe&Pb=volume Pb + volume Fe
Total volume in cylinder = volume water + volume of Pb & Fe.
Answered by
Anonymous
I'm lost in which number goes where
Answered by
DrBob222
C'mon. It makes no sense to me that you don't know which number goes where.
volume Pb = mass/density.
mass Pb = 24.0 g. Right? It says that in the problem.
density = 11.3 g/mL. Right? It says that in the problem.
I think you want someone to work the problem for you.
volume Pb = mass/density.
mass Pb = 24.0 g. Right? It says that in the problem.
density = 11.3 g/mL. Right? It says that in the problem.
I think you want someone to work the problem for you.
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