Question
solve log2(x+1)-log2x=2
Answers
Damon
log2 [(x+1)/x ] = 2
(x+1)/x = 2^2 = 4
x+1 = 4 x
x = 1/3
(x+1)/x = 2^2 = 4
x+1 = 4 x
x = 1/3
anonymous
sorry i meant
log2(2x+1)-log2x=2
log2(2x+1)-log2x=2
Damon
LOL, well do that the same way.
anonymous
is x 1/6
Damon
(2x+1)/x = 4
2 x + 1 = 4x
2 x = 1
x = 1/2
2 x + 1 = 4x
2 x = 1
x = 1/2