Asked by Frank
How do you solve:
log2(x-1)+log2(x-2)=1
I got up to x^2-3x=0
Is it no solution or does it become x(x-3)?
Thanks!
log2(x-1)+log2(x-2)=1
I got up to x^2-3x=0
Is it no solution or does it become x(x-3)?
Thanks!
Answers
Answered by
Steve
x(x-3) = 0
x=0 or 3
but, x=0 does not satisfy the original equation, so the only solution is x=3
x=0 or 3
but, x=0 does not satisfy the original equation, so the only solution is x=3
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