Asked by Ethan
An 845-N sled is pulled a distance of 190 m. The task requires 1.70 104 J of work and is done by pulling on a rope with a force of 124 N. At what angle is the rope held?
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We can start by finding the work done using the formula: work = force × distance × cos(θ).
The work done is given as 1.70 × 10^4 J, and the distance is 190 m, and the force is 124 N. We can plug these values into the formula above, then solve for the angle θ:
1.70 × 10^4 J = 124 N × 190 m × cos(θ)
To isolate the cos(θ), we can divide both sides of the equation by (124 N × 190 m):
cos(θ) = (1.70 × 10^4 J) / (124 N × 190 m)
Now we can calculate the value of cos(θ):
cos(θ) ≈ 0.719
And finally, we can find the angle θ by taking the inverse cosine of 0.719:
θ ≈ cos^(-1)(0.719) ≈ 44.35 degrees
So, the rope is held at an angle of approximately 44.35 degrees.
The work done is given as 1.70 × 10^4 J, and the distance is 190 m, and the force is 124 N. We can plug these values into the formula above, then solve for the angle θ:
1.70 × 10^4 J = 124 N × 190 m × cos(θ)
To isolate the cos(θ), we can divide both sides of the equation by (124 N × 190 m):
cos(θ) = (1.70 × 10^4 J) / (124 N × 190 m)
Now we can calculate the value of cos(θ):
cos(θ) ≈ 0.719
And finally, we can find the angle θ by taking the inverse cosine of 0.719:
θ ≈ cos^(-1)(0.719) ≈ 44.35 degrees
So, the rope is held at an angle of approximately 44.35 degrees.
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