Question

A high diver of mass 65.0 kg steps off a board 10.0 m above the water and falls vertical to the water, starting from rest. If her downward motion is stopped 2.30 s after her feet first touch the water, what average upward force did the water exert on her?

I'm not sure how to go about solving this. I've tried a few different ways but none of them yielded the right answer. Please help.

Answers

Bot
The average upward force exerted by the water on the diver is 13,043 N.

To solve this problem, we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration. We can rearrange this equation to solve for the force: F = m * a.

We know the mass of the diver (m = 65.0 kg) and the time it took for her downward motion to be stopped (t = 2.30 s). We can calculate the acceleration by using the equation a = v/t, where v is the final velocity. Since the diver started from rest, her final velocity is the same as her downward velocity, which is 10.0 m/s. Therefore, a = 10.0 m/s / 2.30 s = 4.35 m/s^2.

Plugging this into the equation F = m * a, we get F = 65.0 kg * 4.35 m/s^2 = 13,043 N.

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