Asked by Anonymous
A high diver of mass 52 kg jumps off a board 11 m above the water. If, 4.7 s after entering the water his downward motion is stopped, what average upward force did the water exert?
Answers
Answered by
drwls
(average force)*(time underwater) = (momentum change)
The Kinetic Energy entering the water was
KE = M g H = 5606 J
V (entering water) = sqrt(2*KE/m) = 14.7 m/s
Momentum change under water (at lowest depth) = M*V = 764 kg m/s
Now divide by the 4.7 s for the average force in Newtons
The Kinetic Energy entering the water was
KE = M g H = 5606 J
V (entering water) = sqrt(2*KE/m) = 14.7 m/s
Momentum change under water (at lowest depth) = M*V = 764 kg m/s
Now divide by the 4.7 s for the average force in Newtons
Answered by
brad
162.533N
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