Asked by Anonymous
A high diver of mass 70 kg jumps off a diving board and enters the water with the speed of 10 m/s the average upward resistance force of water exerts on the diver is 200 N. How far in the water will the diver travel before coming to rest?
Answers
Answered by
Damon
assume hydrostatics is negligible
F = m a
a = 200/70 = 2.86
v = Vi - a t
0 = 10 - 2.86 t
t = 3.5 seconds to stop
d = Vi t - (1/2)(2.86) t^2
d = 10 (3.5) - 1.43 (3.5)^2
d = 35 - 17.5
d = 17.5 meters
well, that is what we get. It is ridiculously high but so be it. Let's hope it is a really, really, deep pool :)
F = m a
a = 200/70 = 2.86
v = Vi - a t
0 = 10 - 2.86 t
t = 3.5 seconds to stop
d = Vi t - (1/2)(2.86) t^2
d = 10 (3.5) - 1.43 (3.5)^2
d = 35 - 17.5
d = 17.5 meters
well, that is what we get. It is ridiculously high but so be it. Let's hope it is a really, really, deep pool :)
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