In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole. With what minimum speed must the athlete leave the ground in order to lift his center of mass 2.00 m and cross the bar with a speed of 0.71 m/s?

Answer 1

Equate energies:
(1/2)mv² = (1/2)m(0.71)²+mg(2.00)
Solve for v.

Answer 2

Thank you!!