Asked by Mary

A rock is thrown vertically upward from ground level at time t=0. At time t=1.3s it passes the top of the tall tower, and 1.1s later it reaches its maximum height. What is the height of the tower?

can someone please get me started....tnx in advance :)
Answered by drwls
The total time T to reach maximum height (where the velocity is zero) is 2.4 s. Use that fact to get the initial velocity Vo.
Vo = g T
Vo = 23.5 m/s

The height of the rock at any time t is
Y = Vo t - (1/2) gt^2
Knowing Vo and that Y = H (height) at t=1.3 s, you can solve for H
Answered by Mary
k tnk u so much....u r ALWAYS a big help...:)
Answered by drwls
You're welcome Mary! I appreciate your taking the time to say so.
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