Asked by KOLEN Bogi Morua
A rock is thrown vertically upward with a speed of 12.0m/s.Exactly 1.00s later a ball thrown up vertically along the same path with a speed of 18.0m/s.
a. At what time will the ball collide with the rock?
a. At what time will the ball collide with the rock?
Answers
Answered by
R_scott
for the rock ... h = -4.9 t^2 + 12.0 t
for the ball ... h = -4.9 (t - 1)^2 + 18.0 (t - 1)
set the two heights equal , and solve for t
for the ball ... h = -4.9 (t - 1)^2 + 18.0 (t - 1)
set the two heights equal , and solve for t
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