Asked by JAMES
Find the remaining trigonometric ratios of θ if sin(θ) is given and θ QI
sin(θ)=7/sqrt 149
cos=
tan=
cot=
csc=
sec=
sin(θ)=7/sqrt 149
cos=
tan=
cot=
csc=
sec=
Answers
Answered by
Henry
sinA = 7/sqrt149 = Y/r.
X^2 + Y^2 = r^2,
X^2 + 7^2 = (sqrt149)^2,
X^2 +49 = 149,
X^2 = 100,
X = 10.
X = 10, Y = 7, r = sqrt149.
cosA = X/r = 10 / sqrt149.
tanA = Y/X = 7 / 10.
cotA = X/Y =
cscA =
secA =
X^2 + Y^2 = r^2,
X^2 + 7^2 = (sqrt149)^2,
X^2 +49 = 149,
X^2 = 100,
X = 10.
X = 10, Y = 7, r = sqrt149.
cosA = X/r = 10 / sqrt149.
tanA = Y/X = 7 / 10.
cotA = X/Y =
cscA =
secA =
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