Asked by Erica
Find the remaining trigonometric values if sin=-3/5 and theta terminates in Quadrent four.
I'm not sure what they're asking
I'm not sure what they're asking
Answers
Answered by
Reiny
For any given angle, there are 6 trig ratios.
They gave you one of them.
sin Ø = -3/5 --- (you have a typo there)
you should know that sinØ = y/r, and r is always positive.
so you have y = -3, r = 5
by Pythagoras, x^2 + y^2 = r^2
x^2 + 9 = 25
x^2 = 16
x = ± 4, but we are told that the angle is in IV,
so x = +4
sinØ = -3/5 ---> that was given
cscØ = -5/3
cosØ = x/r = 4/5
secØ = 5/4
tanØ = y/x = -3/5
cotØ = -5/3
They gave you one of them.
sin Ø = -3/5 --- (you have a typo there)
you should know that sinØ = y/r, and r is always positive.
so you have y = -3, r = 5
by Pythagoras, x^2 + y^2 = r^2
x^2 + 9 = 25
x^2 = 16
x = ± 4, but we are told that the angle is in IV,
so x = +4
sinØ = -3/5 ---> that was given
cscØ = -5/3
cosØ = x/r = 4/5
secØ = 5/4
tanØ = y/x = -3/5
cotØ = -5/3
Answered by
Scott
theta is a Quad IV angle with a sine of -3/5
find cos, tan, sec, csc and cot
find cos, tan, sec, csc and cot
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