Asked by josh
Find the remaining trigonometric ratios of θ if sin(θ) = -1/6 and θ is not in QIII
cos
tan
cot
csc
sec
cos
tan
cot
csc
sec
Answers
Answered by
Damon
so theta is in quadrant 4
triangle (-1)^2 + x^2 = 6^2
x = sqrt 35
cos = (1/6)sqrt 35
tan = -1/sqrt 35
etc
triangle (-1)^2 + x^2 = 6^2
x = sqrt 35
cos = (1/6)sqrt 35
tan = -1/sqrt 35
etc
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