.......CH3NH2 + HOH ==> CH3NH3^+ + OH^-
initial..0.20.............0..........0
change....-x...............x.........x
equil...0.20-x.............x..........x
Kb = (CH3NH3^+)(OH^-)/(CH3NH2)
Substitute into Kb expression from the ICE chart above and solve for x = OH^-, then convert to pOH and to H.
calculate[OH-],[H+] of a .20 M solution of triethylamine Kb=4.0*10^-4
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