Asked by RJ
A mixture weighing 7.290 mg contained only cyclohexane, C6H12 (FM 84.159), and oxirane, C2H4O (FM 44.053). When the mixture was analyzed by combustion analysis, 21.999 mg of CO2 (FM 44.010) were produced. Find the weight percent of oxirane in the mixture.
Answers
Answered by
DrBob222
The combustion equations are as follows:
C6H12 + 9O2 ==> 6CO2 + 6H2O
2C2H4O + 5O2 ==> 4CO2 + 4H2O
This is an equation with two unknowns. Here are the two equations which you should solve simultaneously.
Let Y = milligrams cyclohexane
and Z = milligrams oxirane
===================
Y + Z = 7.290 is eqn 1.
(6Y*44.01/84.159) + (2Z*44.01/44.053) = 21.999 is eqn 2.
After you find Z, then
%Z = (Z(in mg)/7.290)*100 = ?
C6H12 + 9O2 ==> 6CO2 + 6H2O
2C2H4O + 5O2 ==> 4CO2 + 4H2O
This is an equation with two unknowns. Here are the two equations which you should solve simultaneously.
Let Y = milligrams cyclohexane
and Z = milligrams oxirane
===================
Y + Z = 7.290 is eqn 1.
(6Y*44.01/84.159) + (2Z*44.01/44.053) = 21.999 is eqn 2.
After you find Z, then
%Z = (Z(in mg)/7.290)*100 = ?
Answered by
RJ
Thank you DrBob222!
Answered by
kitso
10.5 wt%
Answered by
Imnasa
13%
Answered by
Anonymous
10.8
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