Answers by visitors named: RJ

how can i find out what day of the week December 19,1777 was

if you are 25 and you get 25 dollars every 2 wks and at the end of the month 10% is added like interest how much would you get if you stopped at 65 years old.

I think it's fine. But make sure you can support it in your body paragraphs, otherwise having such a complicated thesis is worthless.

One - monosaccharides. Starch is a carbohydrate made of glucose.

First you do powers. 3(csc(x))^1/2 Then trig. The final: -3(csc(x))^1/2 *(csc(x)cot(x))

14-9x = -80-8x Switch sides. x=94

Axiom

Yes. For example y = -999999x It will be very steep and negative.

Thank you, I was very confused on how to solve it.

4.7 m/s is the correct answer.

Thank you DrBob222!

c=(p*5)+24 p is the dependant

This is how the solution is reached: Centripital acceleration = radius x (angular speed)^2 The acceleration of A = 2.8 (the acceleration of B) So to set it up we get: Sqrt(L2^2+L1^2) w^2 = 2.8 (L1) w^2 The angular velocities cancel because they are equal. Now square both sides to get: (L2^2+L1^2) = 7.84 (L1)^2 Move the L1 over: (L2^2+L1^2)/L1^2=7.84 The fraction can be written: L2^2/L1^2 + L1^2/L1^2 = 7.8 Simplify: L2^2/L1^2 + 1= 7.84 L2^2/L1^2= 6.84 Take the sqrt of that: L2/L1= 2.615 The reciprocal of that is 1/2.615 L1/L2= .382

Thanks, Ms. Sue!!

move the 15 to one side then move the 2.8 to the other then divide out and solve for x. x = 24

Did you find an asnwer

20 000 J

yes, and it is 0.6202∠-172.87 in polar form

.06

A=The area of the horizontal cross section: A(y)=sqrt(3)/4*a^(2) a/(h-y)=s/h --> a=(h-y)(s)/(h) The height for a tetrahedron is: h= sqrt(2/3)(s) --> sqrt(2/3)(7) = 5.7154 a=(h-y)(s)/(h) -->(5.7154-3)(7)/(5.7154) = 3.3257 A(y)=sqrt(3)/4*a^(2) --> sqrt(3)/4*3.3257^(2) = 4.789414 A=4.7894 Volume: V=(s^3)/(6sqrt(2)) --> (7^3)/((6sqrt(2))= 40.42297 V=40.4229

180-50-50=80

I would say all of those except for 3.

80c

Its 42.20

woah

YOU MEAN